In PHP, after assigning a file pointer resource to a variable using the fopen () function, how can I get the file name from a variable?

Question

For instance:

$file = fopen("File.txt", "r");
$filename = $file->basename;

if there is a method like basename for file objects (file pointer resources).

Answer 1

No , the method does not exist. You must save the file name in a variable, for example:

<?php
$filename = "File.txt";
$file = fopen($filename, "r");
$basename = basename($filename);

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Answer 2

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Answer 3

, , PHP tmpfile() - . , Unix. tempnam(realpath(sys_get_temp_dir()), "piclib_");.