What is the best way to handle different forms from one page in Django?

Question

Let's say I have three different forms defined in my opinion:

# views.py
form_one = FormOne()
form_two = FormTwo()
form_three = FormThree()

In my template:

<form action="" method="post" id="form-one">
  {{ form_one.as_table }}
  <input type="submit" value="Submit Form One" name="form-one" />
</form>

<form action="" method="post" id="form-two">
  {{ form_two.as_table }}
  <input type="submit" value="Submit Form Two" name="form-two" />
</form>

<form action="" method="post" id="form-three">
  {{ form_three.as_table }}
  <input type="submit" value="Submit Form Three" name="form-three" />
</form>

Assuming each form has its own unique field names, how do I handle all 3 forms from a single view? I was thinking about the following method, but I'm not sure if this is the best way to solve this problem:

# views.py

if request.method == 'POST':
    request_post = request.POST
    if 'form-one' in request_post:
        form_one = FormOne(request.POST)
    elif 'form-two' in request_post:
        form_two = FormTwo(request.POST)
    else:
        form_three = FormThree(request.POST)
else:
    form_one = FormOne()
    form_two = FormTwo()
    form_three = FormThree()

Any comments or suggestions?

Answer 1

I had a similar problem on the site I'm working on. I have no code with me right now, but I think I have done something in this direction:

if request.method == 'POST': 
    valid = False
    form = FormOne(request.POST) 
    if form.is_valid():
        #handle case where use submitted FormOne
        valid = True

    form = FormTwo(request.POST) 
    if form.is_valid():
        #handle case where use submitted FormTwo
        valid = True

    form = FormThree(request.POST) 
    if form.is_valid():
        #handle case where use submitted FormThree
        valid = True

    if not valid:
        #handle case where none of the forms were valid

Answer 2

- "" . :

if request.method == 'POST':
    form1 = Form1(request.POST, prefix='form1')
    form2 = Form2(request.POST, prefix='form2')
    form3 = Form3(request.POST, prefix='form3')

    if form1.is_valid() and form2.is_valid() and form3.is_valid():
        # Do whatever you have to do
        pass

else:
    form1 = Form1(prefix='form1')
    form2 = Form2(prefix='form2')
    form3 = Form3(prefix='form3')

, :

<form ...>
    {{ form1.as_table }}
    {{ form2.as_table }}
    {{ form3.as_table }}

    <input type="submit" ... />
</form>

Answer 3

• My first thought: can you add '? form_id = 1 'to each action attribute.

  <form action="?form_id=1" method="post" id="form-one">
  

  In view:

  form_id = request.GET.get('form_id', None)
  if form_id == '1':
      form_one = FormOne(request.POST)
  

• Another option is to create separate URLs to submit.

  in urls.py

  url(r'^form1/$', 'someapp.views.process_forms', {'form_class': FormOne}, name='form_one_page'),
  url(r'^form2/$', 'someapp.views.process_forms', {'form_class': FormTwo}, name='form_one_page'),
  url(r'^form3/$', 'someapp.views.process_forms', {'form_class': FormThree}, name='form_one_page'),
  

  in views.py:

  def process_forms(request, form_class=None):
      ...
      form = form_class(data=request.POST)
      ...
  

• You can check if there is a submit button name as you use them in your submit button.

  if request.POST.has_key('form-one'):
      ...
  elif request.POST.has_key('form-two'):
      ...
  elif request.POST.has_key('form-three'):
      ...
  else:
      ...