What is the best way to clean the structure of PHP sites without using a framework?

Question

I work on a medium sized PHP site. I am writing "provider" classes for my objects. Basically, if I have a "user" object, I have a "user-provider" class that can query / store users in the database, receive and return user objects. I just include the providers and dependent objects in the files I need.

I am wondering if this is an easy way to structure a PHP site without a framework, so I am interested in hearing from others that the best way to structure a PHP site is not using a framework.

Answer 1

First of all, there is nothing wrong with using the framework if it does not introduce unnecessary complexity and / or performance penalties for small applications. In PHP, Symfony and Laravel schemes are pretty good in this regard.

Having said that, if you really do not want a “foreign” structure, you still write your own. So it’s better to plan this. Just grab your favorite framework and structure your project exactly as you would when using this framework . Then write the glue code (i.e., your own mini-frame) yourself. If you notice that your project is growing more than expected, you will not have problems with the transition to a "real" structure.

, -, , , . , , , CSS, ..! .

Answer 2

PHP:

• myproject/
  • application/
    • configs/
      • ...
    • controllers/
      • ...
    • views/
      • ...
    • models/
      • ...
    • ...
  • library/
    • PEAR/
    • Zend/
    • ...
  • public/ & larr;
    • index.php
    • library/
      • editarea/
      • jquery/
      • OpenLayers/
      • ...
    • media/
      • ...
    • styles/
      • default.css
      • ...
    • ...

Zend, , , .

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:

• - public/, PHP, Python, Ruby ..
• . (library/ js/, styles/ css/)
• . , , , library styles. , , MVC , , templates/, views/.

Answer 3

: http://www.phpguru.org/static/ApplicationStructure

$_PATHS["base"]      = dirname(dirname(__FILE__)) . "/";
$_PATHS["includes"]  = $_PATHS["base"] . "includes/";
$_PATHS["templates"] = $_PATHS["base"] . "templates/";
$_PATHS["pear"]      = $_PATHS["base"] . "pear/";
$_PATHS["logs"]      = $_PATHS["base"] . "logs/";

, ... :)

Answer 4

. http://en.wikipedia.org/wiki/Model%E2%80%93view%E2%80%93controller