Is it possible to catch a SAXParseException in the JAX-RS / JAXB web service?

I would like to check the JAX-RS web service request so that the correct XML is included in the body. However, this code:

@PUT
@Produces(MediaType.TEXT_XML)
@Consumes(MediaType.TEXT_XML)
@Path("/{objectID}")
public MyObject updateMyObject(@PathParam("objectID") String existingObjectID, JAXBElement<MyObject> object)
{
    MyObject udpatedObject = null;

    try
    {
        udpatedObject = object.getValue();
    }
    catch (Throwable ex)
    {
        throw new WebApplicationException(Response.Status.BAD_REQUEST);            
    }

    // carry one with processing
}

returns an internal internal server 500 error instead of the expected 400 error. Is there a way to catch the exception?

Start of exception stack trace:

Local Exception Stack: 
Exception [EclipseLink-25004] (Eclipse Persistence Services - 2.0.1.v20100213-r6600): org.eclipse.persistence.exceptions.XMLMarshalException
Exception Description: An error occurred unmarshalling the document
Internal Exception: org.xml.sax.SAXParseException: Premature end of file.
at org.eclipse.persistence.exceptions.XMLMarshalException.unmarshalException(XMLMarshalException.java:92)
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1 answer

You can use an exception display unit. When an exception is thrown, it will be translated into the response code:

import javax.persistence.NoResultException;
import javax.ws.rs.core.Response;
import javax.ws.rs.ext.ExceptionMapper;
import javax.ws.rs.ext.Provider;

@Provider
public class XMLMarshalExceptionMapper implements ExceptionMapper<XMLMarshalException> {

    public Response toResponse(XMLMarshalException exception) {
        return Response.status(Response.Status.BAD_REQUEST).build();
    }

}

Talk to:

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Source: https://habr.com/ru/post/1757900/


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