I need to match strings that do not contain a keyword in an arbitrary position

Question

I need to match strings that do not contain the keyword ( beta2) in an arbitrary position.

Consider:

var aStr    = [
                '/beta1/foo',
                'beta1/foo',
                '/beta1_xyz/foo',
                'blahBlah/beta1/foo',
                'beta1',

                '/beta2/foo',
                'beta2/foo',
                '/beta2_xyz/foo',
                'blahBlah/beta2/foo',
                'beta2',

                '/beat2/foo',
                'beat2/foo',
                '/beat2_xyz/foo',
                'blahBlah/beat2/foo',
                'beat2'
            ];

function bTestForMatch (Str)
{
    return /.*\b(?!beta2).*/i.test (Str);
}

for (var J=0, iLen=aStr.length;  J < iLen;  J++)
{
    console.log (J, bTestForMatch (aStr[J]), aStr[J]);
}

We need a regular expression that matches all lines that exclude beta2. beta2always begins with the word boundary, but does not necessarily end with one. It can be in various positions in a row.

Desired Results:

 0    true    /beta1/foo
 1    true    beta1/foo
 2    true    /beta1_xyz/foo
 3    true    blahBlah/beta1/foo
 4    true    beta1
 5    false   /beta2/foo
 6    false   beta2/foo
 7    false   /beta2_xyz/foo
 8    false   blahBlah/beta2/foo
 9    false   beta2
10    true    /beat2/foo
11    true    beat2/foo
12    true    /beat2_xyz/foo
13    true    blahBlah/beat2/foo
14    true    beat2

---

A regular expression is used for a third-party analysis tool that accepts JavaScript regular expressions to filter subsamples. The tool takes one line of regular expression. The API is missing and we do not have access to its source code.

JavaScript-, - (beta2) ?

Answer 1

Try

/^(?!.*beta2).*$/

Answer 2

?

return !/beta2/i.test (Str);