As an alternative:
>>> hexstring = "01234567"
>>> it=iter(hexstring); [a+b for a,b in zip(it, it)]
['01', '23', '45', '67']
Use itertools.izipinstead zipif you are targeting Python 2.x.
This method is the specific version grouperin the itertools recipe.
Some micro tests:
$ python2.6 -m timeit -s 'hexstring = "01234567"*500' '[hexstring[i:i+2] for i in xrange(0,len(hexstring), 2)]'
1000 loops, best of 3: 409 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"*500' '[hexstring[i:i+2] for i in range(0,len(hexstring), 2)]'
1000 loops, best of 3: 438 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"*500' 'it=iter(hexstring); [a+b for a,b in zip(it, it)]'
1000 loops, best of 3: 526 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"*500; from itertools import izip' 'it=iter(hexstring); [a+b for a,b in izip(it, it)]'
1000 loops, best of 3: 406 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"*500; import re; r=re.compile(".{1,2}"); f=r.findall' 'f(hexstring)'
1000 loops, best of 3: 458 usec per loop
$ python3.1 -m timeit -s 'hexstring = "01234567"*500' '[hexstring[i:i+2] for i in range(0,len(hexstring), 2)]'
1000 loops, best of 3: 756 usec per loop
$ python3.1 -m timeit -s 'hexstring = "01234567"*500' 'it=iter(hexstring); [a+b for a,b in zip(it, it)]'
1000 loops, best of 3: 414 usec per loop
$ python3.1 -m timeit -s 'hexstring = "01234567"*500; import re; r=re.compile(".{1,2}"); f=r.findall' 'f(hexstring)'
1000 loops, best of 3: 865 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"' '[hexstring[i:i+2] for i in xrange(0,len(hexstring), 2)]'
1000000 loops, best of 3: 1.52 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"' '[hexstring[i:i+2] for i in range(0,len(hexstring), 2)]'
1000000 loops, best of 3: 1.76 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"' 'it=iter(hexstring); [a+b for a,b in zip(it, it)]'
100000 loops, best of 3: 3.78 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"; from itertools import izip' 'it=iter(hexstring); [a+b for a,b in izip(it, it)]'
100000 loops, best of 3: 2.39 usec per loop
$ python2.6 -m timeit -s 'hexstring = "01234567"; import re; r=re.compile(".{1,2}"); f=r.findall' 'f(hexstring)'
1000000 loops, best of 3: 1.45 usec per loop
$ python3.1 -m timeit -s 'hexstring = "01234567"' '[hexstring[i:i+2] for i in range(0,len(hexstring), 2)]'
100000 loops, best of 3: 2.46 usec per loop
$ python3.1 -m timeit -s 'hexstring = "01234567"' 'it=iter(hexstring); [a+b for a,b in zip(it, it)]'
1000000 loops, best of 3: 1.84 usec per loop
$ python3.1 -m timeit -s 'hexstring = "01234567"; import re; r=re.compile(".{1,2}"); f=r.findall' 'f(hexstring)'
100000 loops, best of 3: 2.07 usec per loop
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