How does char * blah = hello work?

Question

When you create a string from pointers char, how does it work?

char *name = "ben";

Is this a "hidden" pointer arithmetic?

Answer 1

There is no hidden pointer arithmetic, but I suspect you want a more detailed answer.

If you have a function:

void foo() {
    char * bar = "Hello World";
}

There are actually two pieces of memory:

• -, 12 "Hello World" (1 NULL ). . ( ) ( segfault).
• - , bar. foo(), (4 32 ) . , foo().

, :

bar = "Good bye";

"Hello World" "Good bye". 3- "Good bye" ( ), (bar) , .

---

"" ​​( ) :

void foo() {
    char bar[] = "Hello World";
}

, (, ). , , , ( "Hello World" + ), .

, gcc -S test.c, test.s.

---

- C.

, , , , , , ( ).

Answer 2

. , .

, , "ben" ( .rodata ELF), name .

Answer 3

"" ?

. . , *. .

Answer 4

C - , , n '\ 0' . char * p = "string", p.

, , "ben" "b", "e", "n" "\ 0" . , . . 'name' , , , .

Answer 5

- , :

char name[] = "ben";

Answer 6

name - , "b" ( "h" ). , . .

Answer 7

​​, , , ( ). , , , . , , "const", . , , seg.