Zip function for shell scripts

Question

I am trying to write a shell script that will have makemultiple targets on several different paths. I will give a list of paths separated by spaces, and a list of goals separated by spaces, and the script will be make DESTDIR=$path $targetfor each pair of paths and goals. In Python, my script would look something like this:

for path, target in zip(paths, targets):
    exec_shell_command('make DESTDIR=' + path + ' ' + target)

However, this is my current shell script:

#! /bin/bash

packages=$1
targets=$2
target=

set_target_number () {
    number=$1
    counter=0
    for temp_target in $targets; do
        if [[ $counter -eq $number ]]; then
            target=$temp_target
        fi
        counter=`expr $counter + 1`
    done 
}

package_num=0
for package in $packages; do
    package_fs="debian/tmp/$package"
    set_target_number $package_num
    echo "mkdir -p $package_fs"
    echo "make DESTDIR=$package_fs $target"
    package_num=`expr $package_num + 1`
done

Is there a Unix tool equivalent to a Python zip function function or an easier way to get an item from a list, separated by a space, by its index? Thank.

Answer 1

Use an array:

#!/bin/bash
packages=($1)
targets=($2)
if (("${#packages[@]}" != "${#targets[@]}"))
then
    echo 'Number of packages and number of targets differ' >&2
    exit 1
fi
for index in "${!packages[@]}"
do
    package="${packages[$index]}"
    target="${targets[$index]}"
    package_fs="debian/tmp/$package"
    mkdir -p "$package_fs"
    make "DESTDIR=$package_fs" "$target"
done

Answer 2

bash. , , .

Answer 3

paste -d ' ' paths targets | sed 's/^/make DESTDIR=/' | sh

pasteequivalent zipin shell. sedused to add the make command (using regex), and the result is passed shto execute