__COUNTER__ equivalent on Xcode?

Question

I am migrating a project from Linux to Xcode, and I am facing a "version" problem.

I need a unique compile time identifier for my dynamic stuff, on linux I used the __ COUNTER__ preprocessor, but it seems that the gcc 4.2 used in Xcode doesn't know about __ COUNTER__ yet ...
So, I was wondering what I can do to solve this?
I can upgrade GCC to 4.3 (which __ COUNTER__ understands) using macports.org or something like that ... I am very noob on OSX and not very good on linux = [
or find another way to accomplish this, in case method to give a function / variable a unique identifier. I tried with __ LINE__, but after a few days you end up declaring the material on the same line in different files, and playing with this is simply not productive ...

Any help is appreciated!

Thanks
Jonathan

Answer 1

@ stinky472: I am using code close to what you wrote above ...

My problem was that I used a macro to declare project namespaces, so having a fully qualified class name, such as class c, is in :: b :: c.
I changed my code to not rely on namespaces, but add a new argument in the class macro declaration to indicate which namespace is used, for example:

newclass (a :: b, c): public d {

};

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Answer 2

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#include <iostream>
#include <string>
using namespace std;

template <class T>
const char* my_type_id()
{
    return "Unknown";
}

#define REGISTER_TYPE(some_type)            \
    template <> inline                      \
    const char* my_type_id<some_type>()     \
    {                                       \
        return #some_type;                  \
    }

REGISTER_TYPE(int)
REGISTER_TYPE(std::string)

int main()
{
    // displays "int"
    cout << my_type_id<int>() << endl;

    // displays "std::string"
    cout << my_type_id<string>() << endl;

    // displays "Unknown" - we haven't registered char
    cout << my_type_id<char>() << endl;
}

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