Error passing * as shell argument in C

Question

I am developing a small program where I provide command line arguments

For example,. / A.out 2 3 4 + *

When it arrives "*", instead of typing "*" itself, it prints folders inside the "+" directory works fine. Please let me know how to remove this error. I want to type '*' here.

#include <stdio.h>
int main(int argc, char *argv[])
{
   char *c;

   while(--argc > 0)
   {
      c = *++argv;
      if(strcmp(c,"+") == 0 )
      {
          printf("%s",c);
      }
      else if(strcmp(c,"-") == 0)
      {
          printf("%s",c);
      }
      else if(c[0] == '*')
      {
          printf("%s",c);
      }
   }
}

Answer 1

This has nothing to do with your code, but rather with your shell. If you want the shell to not hide wildcards, you will need to avoid them, either with a backslash or with quotation marks.

./foo \*
./bar '*'

Answer 2

'*' . , , .

:

./a.out 2 3 4 +\*