Is std :: vector the same as array [number]?

Question

Possible duplicate:
Do std :: vector elements guarantee continuity?

Does std :: vector always contain data in sequential memory addresses as an array of [number]?

Answer 1

For all types except bool, the standard requires elements to be contiguous in memory:

23.2.4 / 1 ... Elements of a vector are stored adjacent, which means that if v is a vector, where T is some type other than bool, then it obeys the identifier & v [n] == & v, v [0] + n for all 0 <= n <V.SIZE ()

Keep in mind that it std::vector<bool>has special requirements and does not match the bool array.

Answer 2

. :

std::vector<int> arr;

,

&arr[0]

int, () API.

Answer 3

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Answer 4

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Answer 5

When using the standard allocator, you can be sure that the allocated memory is continuous when using std :: vector. In other words, foo [n + 1] is the next element in the sequence after foo [n]. But std :: vector is not an array like

int* blah = new int[100];

not an array. But

int blah[100];

created on the stack is an array. Pointers to allocated memory and arrays just use semantics. They are not equal by standard, so do not confuse them.