Sort nesting by name while maintaining integrity

Question

I am using a nested set model that will later be used to create a sitemap for my website. This is my table structure.

create table departments (
    id int identity(0, 1) primary key
    , lft int
    , rgt int
    , name nvarchar(60)
);

insert into departments (lft, rgt, name) values (1, 10, 'departments');
insert into departments (lft, rgt, name) values (2, 3, 'd');
insert into departments (lft, rgt, name) values (4, 9, 'a');
insert into departments (lft, rgt, name) values (5, 6, 'b');
insert into departments (lft, rgt, name) values (7, 8, 'c');

How can I sort by depth as well as by name? I can do

select
    replicate('----', count(parent.name) - 1) + ' ' + node.name
    , count(parent.name) - 1 as depth
, node.lft
from
    departments node
    , departments parent
where
    node.lft between parent.lft and parent.rgt
group by
    node.name, node.lft
order by
    depth asc, node.name asc;

However, for some reason this does not match children with parents.

department      lft     rgt
---------------------------
 departments    0       1
---- a        1        4
---- d        1        2
-------- b    2        5
-------- c    2        7

As you can see, department 'd' has department 'children!

Thank.

Answer 1

, ANSI SQL. , , , node, , node, . , , . , , :

SELECT
    N1.name
FROM
    dbo.departments N1
ORDER BY
    (
    SELECT
        COUNT(DISTINCT N2.lft)
    FROM
        dbo.departments N2
    INNER JOIN (
                SELECT
                    N.name,
                    N.lft,
                    N.rgt,
                    (SELECT COUNT(*) FROM dbo.departments WHERE lft < N.lft AND rgt > N.lft) AS depth
                FROM
                    dbo.departments N) SQ1 ON
        SQ1.lft <= N2.lft AND SQ1.rgt >= N2.lft
    INNER JOIN (
                SELECT
                    N3.name,
                    N3.lft,
                    N3.rgt,
                    (SELECT COUNT(*) FROM dbo.departments WHERE lft < N3.lft AND rgt > N3.lft) AS depth
                FROM
                    dbo.departments N3) SQ2 ON
        SQ2.lft <= N1.lft AND SQ2.rgt >= N1.lft AND
        SQ2.depth = SQ1.depth AND
        SQ2.name > SQ1.name
    )

, - , .

Answer 2

, "-", . . CTE, SQL Server, . ANSI SQL, .

;WITH Tree_Path AS (
    SELECT
        lft,
        rgt,
        name,
        CAST(name + '-' AS VARCHAR(MAX)) AS tree_path,
        1 AS depth
    FROM
        dbo.departments
    WHERE
        lft = 1
    UNION ALL
    SELECT
        c.lft,
        c.rgt,
        c.name,
        CAST(tp.tree_path + c.name + '-' AS VARCHAR(MAX)),
        tp.depth + 1
    FROM
        Tree_Path tp
    INNER JOIN dbo.departments AS c ON
        c.lft > tp.lft AND
        c.lft < tp.rgt AND
        NOT EXISTS (SELECT * FROM dbo.departments d WHERE d.lft < c.lft AND d.rgt > c.lft AND d.lft > tp.lft AND d.lft < tp.rgt))
SELECT
    REPLICATE('----', depth - 1) + name,
    depth - 1,
    lft
FROM
    Tree_Path
ORDER BY
    tree_path,
    name

Answer 3

. : node.name, depth node.lft - :

department      lft     rgt

, - , -, , , . a, d - .

If you want the number of subtrees and nested set to be supported properly, the query is simple:

SELECT 
    D1.name,
    (D1.rgt - D1.lft - 1) / 2    AS SubordinateDepartments
FROM
    departments AS D1
ORDER BY
    SubordinateDepartments DESC,
    D1.name