PHPExcel writes Excel and saves on server?

Question

The code I currently have is:

<?php

  /** PHPExcel */
  require_once '../Classes/PHPExcel.php';

  /** PHPExcel_IOFactory */
  require_once '../Classes/PHPExcel/IOFactory.php';

  // Create new PHPExcel object
  $objPHPExcel = new PHPExcel();

  // Set properties
  $objPHPExcel->getProperties()->setCreator("Maarten Balliauw")
                               ->setLastModifiedBy("Maarten Balliauw")
                               ->setTitle("Office 2007 XLSX Test Document")
                               ->setSubject("Office 2007 XLSX Test Document")
                               ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.")
                               ->setKeywords("office 2007 openxml php")
                               ->setCategory("Test result file");

  $result = 'select * from table1';

  for($i=0;$i<count($result);$i++) {

    $result1 = 'select * from table2 where table1_id = ' . $result[$i]['table1_id'];

    for ($j=0;$j<count($result1);$j++) {
      $objPHPExcel->setActiveSheetIndex(0)->setCellValue('A' . $j, $result1[$j]['name']);
    }

    // Set active sheet index to the first sheet, so Excel opens this as the first sheet
    $objPHPExcel->setActiveSheetIndex(0);

    // Save Excel 2007 file
    $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007');
    $objWriter->save(str_replace('.php', '.xlsx', __FILE__));

    // Echo done
    echo date('H:i:s') . " Done writing file.\r\n";       
  }

?>

The above code executes and saves n files .xlsxin a folder, but the problem I get is the biggest one count(result1)in the loop forexecuted in all saved excel files.

Answer 1

Before delving, one thing is clear:

You did not execute the query for $ result, do not retrieve it and the query $ result1 that you use, which is impossible,

A similar problem exists with $ result1

You can use:

$result = mysql_query('select * from table1');
while($fetch_result=mysql_fetch_array($result))
{
    $result2 = mysql("select * from table2 where table1_id = '".$fetch_result['table1_id']."'");

   while($fetch_result2=mysql_fetch_array($result2)
   {
    --your code--

But it is preferable to write JOIN instead of these two queries

Answer 2

mysql_num_rows - http://php.net/manual/en/function.mysql-num-rows.php

$q = 'select * from table1';
$res = mysql_query($q);
$count = mysql_num_rows($result);

for ($j=0;$j<$count;$j++) {
    #code here
}

mysql_fetch_assoc