A way to solve this problem is to use an overloaded one AwaitEvent, which allows you to wait for two events. Instead of waiting, MouseMoveyou can also wait for the event MouseUp- in the first case, you can continue moving, and in the second case, you can return from the loop and stop the drag and drop (this is actually discussed later in the book in section 16.4.5).
- AwaitObservable (. ), , Observable.map ( , ),
let! args = Async.AwaitObservable(layoutRoot.MouseMove, layoutRoot.MouseUp)
match args with
| Choice1Of2(args) ->
// Handle the 'MouseMove' event with 'args' here
Canvas.SetLeft(rectangle1, args.GetPosition(layoutRoot).X)
Canvas.SetTop(rectangle1, args.GetPosition(layoutRoot).Y)
return! drag()
| Choice2Of2(_) ->
// Handle the 'MouseUp' event here
return()
, AwaitObservable F # (), t -, :
// Adds 'AwaitObservable' that takes two observables and returns
// Choice<'a, 'b> containing either Choice1Of2 or Choice2Of2 depending
// on which of the observables occurred first
type Microsoft.FSharp.Control.Async with
static member AwaitObservable(ev1:IObservable<'a>, ev2:IObservable<'b>) =
Async.FromContinuations((fun (cont,econt,ccont) ->
let rec callback1 = (fun value ->
remover1.Dispose()
remover2.Dispose()
cont(Choice1Of2(value)) )
and callback2 = (fun value ->
remover1.Dispose()
remover2.Dispose()
cont(Choice2Of2(value)) )
// Attach handlers to both observables
and remover1 : IDisposable = ev1.Subscribe(callback1)
and remover2 : IDisposable = ev2.Subscribe(callback2)
() ))