Typeof based factory or is

Question

What a more elegant way to have the code below, where I want to return a derived class depending on the type of another class.

            if (option_ is Rectangle)
            {
                modelInputs = new Foo();
            }
            else if (option_ is Circle)
            {
                modelInputs = new Bar();
            }
            else if (option_ is Triangle)
            {
                modelInputs = new Bar2();
            }

Answer 1

Rectangle, Circle, and Triangle implement IHasModelInput:

interface IHasModelInput
{
    IModelInput GetModelInput();
}

then you can do

IModelInput modelInputs = option_.GetModelInput();

Answer 2

My opinion: your "inelegant" way is in order. It is simple, readable and does the job.

Rectangle, Circle Triangle factory IHasModelInput, : IModelInput (Foo, Bar Bar2). , , , .

. , factory .

    public static class FactoryMethod<T>  where T : IModelInput, new()
    {
        public static IModelInput Create()
        {
            return new T();
        }
    }

    delegate IModelInput ModelInputCreateFunction();

    IModelInput CreateIModelInput(object item)
    {

        Dictionary<Type, ModelInputCreateFunction> factory = new Dictionary<Type, ModelInputCreateFunction>();


        factory.Add(typeof(Rectangle), FactoryMethod<Foo>.Create);
        factory.Add(typeof(Circle),    FactoryMethod<Bar>.Create);
        // Add more type mappings here




        IModelInput modelInput;
        foreach (Type t in factory.Keys)
        {
            if ( item.GetType().IsSubclassOf(t) || item.GetType().Equals(t))
            {
                modelInput = factory[t].Invoke();
                break;
            }
        }
        return modelInput;
    }

: ?

Answer 3

Hashtable , , Activator.CreateInstance factoryin:

Hashtable ht = new Hashtable();
ht.Add(typeof(Rectangle), typeof(Bar));
ht.Add(typeof(Square), typeof(Bar2));

modelInputs = Activator.CreateInstance(ht[option.GetType()]);

, Activator.CreateInstance - .NET. , , .

Answer 4

You can associate a type with the option_ option if it permits, and then just create an instance from it.

Answer 5

I usually use a factory method like this, when I want to convert a string to a type at runtime, I use a dictionary that matches the string to the type.

Like this from a recent project:

public class TaskFactory
{
    private Dictionary<String, Type> _taskTypes = new Dictionary<String, Type>();

    public TaskFactory()
    {
        // Preload the Task Types into a dictionary so we can look them up later
        foreach (Type type in typeof(TaskFactory).Assembly.GetTypes())
        {
            if (type.IsSubclassOf(typeof(CCTask)))
            {
                _taskTypes[type.Name.ToLower()] = type;
            }
        }
    }

    public CCTask CreateTask(XmlElement task)
    {
        if (task != null)
        {
            string taskName = task.Name;
            taskName =  taskName.ToLower() + "task";

            // If the Type information is in our Dictionary, instantiate a new instance of that task
            Type taskType;
            if (_taskTypes.TryGetValue(taskName, out taskType))
            {
                return (CCTask)Activator.CreateInstance(taskType, task);
            }
            else
            {
                throw new ArgumentException("Unrecognized Task:" + task.Name);
            }                               
        }
        else
        {
            return null;
        }
    }
}