How to call that starts with * in iPhone?

In my application, I want to call * 111 when I use this tel: * 111 URL to call, but I cannot succeed in the call, please give me some directions, thank you very much.

[[UIApplication sharedApplication] openURL:@"tel:*111"] 

does not work. but it will work on uninstall *:

[[UIApplication sharedApplication] openURL:@"tel:111"];
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1 answer

It's impossible. From Apple URL Schema Link :

, "" , , . , URL- * #, "" .

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Source: https://habr.com/ru/post/1748129/


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