Why does a derived class constructor always access the base class constructor?

Question

I saw this question in one of my question docs:

Why should the constructor of the derived class always refer to the constructor of the base class?

I am wondering if the question is really?

Answer 1

So that you can have a valid Base object before you start messing around with the inherited functions of your derived object!

Answer 2

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Answer 3

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Answer 7

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, super() subclasses.

The visible part of building a class is initializing the fields. But there is still under the hood (memory allocation, registration, etc.). All of this must be done for all superclasses when creating a derived class.