SQL Server: get an entry in the top xx blog from Umbraco by parameter

Question

The following SQL will get what I need:

 SELECT TOP (50) [nodeId] 
 FROM [dbo].[cmsContentXml] 
 WHERE [xml] like '%creatorID="29"%'    
   AND [xml] like '%nodeType="1086"%' 
 ORDER BY [nodeId] DESC

I need to pass the numbers as parameters, so I follow:

exec sp_executesql N'SELECT TOP (@max) [nodeId] FROM [dbo].[cmsContentXml] WHERE [xml] like ''%creatorID="@creatorID"%''    AND [xml] like ''%nodeType="@nodeType"%'' ORDER BY [nodeId] DESC',N'@max int,@creatorID int,@nodeType int',@max=50,@creatorID=29,@nodeType=1086

which, however, does not return any record, any idea?

Answer 1

Try changing the SQL statement so that you build the statement by adding parameters when you submit them as part of the statement, for example.

'SELECT TOP ' + @max + ' [nodeId] '.....

Answer 2

The problem is how you try to use parameters in LIKE clauses.

. @creatorID @nodeType LIKE - xml, (, LITERALLY "% creatorID =" @creatorID "

, :

SELECT TOP (@max) [nodeId] 
FROM [dbo].[cmsContentXml] 
WHERE [xml] like '%creatorID="@creatorID"%'
    AND [xml] like '%nodeType="@nodeType"%' 
ORDER BY [nodeId] DESC

:

SELECT TOP (@max) [nodeId] 
FROM [dbo].[cmsContentXml] 
WHERE [xml] like '%creatorID="' + CAST(@creatorID AS VARCHAR(50)) + '"%'
    AND [xml] like '%nodeType="' + CAST(@nodeType AS VARCHAR(50)) + '"%' 
ORDER BY [nodeId] DESC

- :

DECLARE @SQL NVARCHAR(1000)
SET @SQL = '
    SELECT TOP (@max) [nodeId] 
    FROM [dbo].[cmsContentXml] 
    WHERE [xml] like ''%creatorID="'' + CAST(@creatorID AS VARCHAR(50)) + ''"%''    
       AND [xml] like ''%nodeType="'' + CAST(@nodeType AS VARCHAR(50)) + ''"%'' 
    ORDER BY [nodeId] DESC'

exec sp_executesql @SQL,
    N'@max int,@creatorID int,@nodeType int',
    @max=50,@creatorID=29,@nodeType=1086