In .NET Xml Serialization, is it possible to serialize a class with an enum property with different tags based on the value of the property?

Question

I have a class containing a list property in which the list contains objects that have the enum property.

When I serialize this, it looks like this:

<?xml version="1.0" encoding="ibm850"?>
<test>
  <events>
    <test-event type="changing" />
    <test-event type="changed" />
  </events>
</test>

Is it possible, through attributes or the like, to make Xml look like this?

<?xml version="1.0" encoding="ibm850"?>
<test>
  <events>
    <changing />
    <changed />
  </events>
</test>

Basically, use the value of an enumeration property as a way to determine the tag name? Is using a class hierarchy (i.e., subclassing instead of using a property value) the only way?

Change . After testing, it seems that even the class hierarchy does not actually work. If there is a way to structure classes to get the result I want, even with subclasses, this is also an acceptable answer.

, Xml ( Ctrl + F5 Visual Studio, ):

using System;
using System.Collections.Generic;
using System.Xml.Serialization;

namespace ConsoleApplication18
{
    public enum TestEventTypes
    {
        [XmlEnum("changing")]
        Changing,

        [XmlEnum("changed")]
        Changed
    }
    [XmlType("test-event")]
    public class TestEvent
    {
        [XmlAttribute("type")]
        public TestEventTypes Type { get; set; }
    }
    [XmlType("test")]
    public class Test
    {
        private List<TestEvent> _Events = new List<TestEvent>();

        [XmlArray("events")]
        public List<TestEvent> Events { get { return _Events; } }
    }

    class Program
    {
        static void Main(string[] args)
        {
            Test test = new Test();
            test.Events.Add(new TestEvent { Type = TestEventTypes.Changing });
            test.Events.Add(new TestEvent { Type = TestEventTypes.Changed });

            XmlSerializer serializer = new XmlSerializer(typeof(Test));
            XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
            ns.Add("", "");
            serializer.Serialize(Console.Out, test, ns);
        }
    }
}

Answer 1

    public class Test : IXmlSerializable
    {
        private List<TestEvent> _Events = new List<TestEvent>();

        public List<TestEvent> Events { get { return _Events; } }

        #region IXmlSerializable Members

        public System.Xml.Schema.XmlSchema GetSchema()
        {
            return null;
        }

        public void ReadXml(System.Xml.XmlReader reader)
        {
            throw new NotImplementedException();
        }

        public void WriteXml(System.Xml.XmlWriter writer)
        {
            writer.WriteStartElement("events");
            foreach (var item in Events)
            {
                writer.WriteElementString(item.Type.ToString().ToLower(), "");
            }
            writer.WriteEndElement();
        }

        #endregion
    }

Test , . , , XmlType Test, , Test .

Answer 2

, - XmlType. , DataContractSerializer. OnSerializing, , .