Best way to get friends for php / mysql social network

Question

I have a social network similar to myspace, but I use PHP and mysql, I was looking for the best way to show only published bulletins of fronm themself users and from users with whom they became friends.

This includes 3 tables.

friend_friend = this table stores records of who is who friend_bulletins = this stores newsletters friend_reg_user = this is the main user table with all user data, such as name and photo URL

I will publish the table of the bulletin tables and friends below, I will publish the fields that are important for the user table.

- Table structure for table friend_bulletin

CREATE TABLE IF NOT EXISTS `friend_bulletin` (
  `auto_id` int(11) NOT NULL AUTO_INCREMENT,
  `user_id` int(10) NOT NULL DEFAULT '0',
  `bulletin` text NOT NULL,
  `subject` varchar(255) NOT NULL DEFAULT '',
  `color` varchar(6) NOT NULL DEFAULT '000000',
  `submit_date` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `status` enum('Active','In Active') NOT NULL DEFAULT 'Active',
  `spam` enum('0','1') NOT NULL DEFAULT '1',
  PRIMARY KEY (`auto_id`),
  KEY `user_id` (`user_id`),
  KEY `submit_date` (`submit_date`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=245144 ;

- Table structure for table friend_friend

CREATE TABLE IF NOT EXISTS `friend_friend` (
  `autoid` int(11) NOT NULL AUTO_INCREMENT,
  `userid` int(10) DEFAULT NULL,
  `friendid` int(10) DEFAULT NULL,
  `status` enum('1','0','3') NOT NULL DEFAULT '0',
  `submit_date` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `alert_message` enum('yes','no') NOT NULL DEFAULT 'yes',
  PRIMARY KEY (`autoid`),
  KEY `userid` (`userid`),
  KEY `friendid` (`friendid`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=2657259 ;

friend_reg_user, auto_id = disp_name = pic_url = .

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//1

SELECT auto_id, user_id, bulletin, subject, color, fb.submit_date, spam
FROM friend_bulletin AS fb
WHERE (user_id IN (SELECT userid FROM friend_friend WHERE friendid = $MY_ID AND status =1) OR user_id = $MY_ID)
ORDER BY auto_id

// , , $str_friend_ids = "1,2,3,4,5,6,7,8"

select auto_id,subject,submit_date,user_id,color,spam
from friend_bulletin
where user_id=$MY_ID or user_id in ($str_friend_ids) 
order by auto_id DESC

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SELECT fb.auto_id, fb.user_id, fb.bulletin, fb.subject, fb.color, fb.submit_date, fru.disp_name, fru.pic_url
FROM friend_bulletin AS fb
LEFT JOIN friend_friend AS ff ON fb.user_id = ff.userid
LEFT JOIN friend_reg_user AS fru ON fb.user_id = fru.auto_id
WHERE (
ff.friendid =1
AND ff.status =1
)
LIMIT 0 , 30

Answer 1

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