Bash: any command to replace strings in text files?

Question

I have a hierarchy of directories containing many text files. I would like to search for a specific text line every time it appears in one of the files, and replace it with another line. For example, I can replace each occurrence of the string "Coke" with "Pepsi". Does anyone know how to do this? I am wondering if there is some kind of Bash command that can do this without loading all of these files into the editor or without creating a more complex script to do this.

I found this page explaining the trick with sed, but it does not work on files in subdirectories.

Answer 1

Use sedin conjunction with find. For instance:

find . -name "*.txt" | xargs sed -i s/Coke/Pepsi/g

or

find . -name "*.txt" -exec sed -i s/Coke/Pepsi/g {} \;

(see search man page for more information)

Answer 2

IMO, the tool with the easiest use for this task is rpl:

rpl -R Coke Pepsi .

( -Rfor recursive replacement in all subdirectories)

Answer 3

sed find :

find . -name "file.*" -exec sed -i 's/Coke/Pepsi/g' {} \;

Answer 4

find . -type f -exec sed -i 's/old-word/new-word/g' {} \;

Answer 5

perl. - , , :

% perl -pi -e 's/Coke/Pepsi/g;' $filename

EDIT

% find ./ -exec perl -pi -e 's/Coke/Pepsi/g;' {} \;

Answer 6

find sed

Answer 7

:

find ed

http://codesnippets.joyent.com/posts/show/2299

( -t)