Regular expression in C #

Question

I have text similar to this.

@@ MMIVLoader @ProductVer @ 4.1.2 @ BCM_7400S_LE @Product @ 08.21.2009 @
@@ MMIVLib @ObjectVer @ 4.1.2 @ BCM_7400S_LE @ Product @ August 21, 2009 @
@@ HuaweFGDLDrv @ObjectVer @ 01.00.09 @ 7324 @PRODUCT @
08.20.2009 @ @@ ProtectVer @ObjectVer @ 127.8.1 @ BCM_SDE5.03 @PRODUCT @Aug 4 2009 06: 56: 19 @
@@ KernelSw @ObjectVer @ 0.0.1 @ BCM-7454 @PRODUCT @Dec 19 2007 @
@ @ReceiverSw @ObjectVer @ E.5.6.001 @ HWBC01ZS @PRODUCT @ May 3, 2010 @

I want out to fit into an array like

MMIVLoader 4.1.2
MMIVLib         4.1.2
HuaweFGDLDrv 01.00.09
ProtectVer 127.8.1 
KernelSw 0.0.1
ReceiverSw E.5.6.001

Can someone suggest me how to do this in C # using regex or is there any tricky way to do this

early

Answer 1

, @ ( ) .

var list = myString.Split(new String[] {Environment.NewLine},
          StringSplitOptions.RemoveEmptyEntries)                
   .Select(item => item.Split(new char[] {'@'}, 
          StringSplitOptions.RemoveEmptyEntries))
   .Where(a => a.Length > 2)
   .Select(a => new { Item = a[0], Version = a[2] }).ToArray();

Answer 2

Regex.Replace(text, @"^@@([^@]+)@[^@]+@([^@]+).*", "$1,$2",RegexOptions.Multiline);

MMIVLoader,4.1.2
MMIVLib,4.1.2
HuaweFGDLDrv,01.00.09
ProtectVer,127.8.1
KernelSw,0.0.1
ReceiverSw,E.5.6.001

,

Answer 3

If you need a crazy regex, you can use this:

var matches = Regex.Matches(
    input,
    "@@(?<name>.*?)@(Product|Object)Ver@(?<ver>.*?)@",
    RegexOptions.IgnoreCase
).Cast<Match>().Select(m => m.Groups);

foreach (var match in matches)
{
    Console.WriteLine("{0} {1}", match["name"], match["ver"]);
}

Answer 4

For completeness, here is the LINQ version with query syntax :)

string[] lines = new string[] { 
            "@@MMIVLoader@ProductVer@4.1.2@BCM_7400S_LE@Product@Aug 21 2009@",
            "@@MMIVLib@ObjectVer@4.1.2@BCM_7400S_LE@Product@Aug 21 2009@",
            "@@HuaweFGDLDrv@ObjectVer@01.00.09@7324@PRODUCT@Aug 20 2009@",
            "@@ProtectVer@ObjectVer@127.8.1 @BCM_SDE5.03@PRODUCT@Aug  4 2009 06:56:19@",
            "@@KernelSw@ObjectVer@0.0.1@BCM-7454@PRODUCT@ Dec 19 2007@",
            "@@ReceiverSw@ObjectVer@E.5.6.001@HWBC01ZS@PRODUCT@May  3 2010@" };
var q = from components in
           (from line in lines
            select line.Split(new char[] { '@' }, 
                     StringSplitOptions.RemoveEmptyEntries))
        select new { Name = components[0], Version = components[2] };
foreach (var item in q)
{
    Console.WriteLine("Item: Name={0} Version={1}", item.Name, item.Version);
}