Is 2 + 3 considered a literal?

Question

Suppose I have something like

int x = 2 + 3;

Is it xconsidered a literal?

Answer 1

x- symbol. 2 + 3- expression. 2and 3are literals.

Answer 2

No, these are two literals in a compile-time constant expression. Depending on how it compiles, you may not be able to distinguish the resulting binary.

Answer 3

• int - ,
• x - ,
• = -
• 2 -
• + -
• 3 -
• ; -

Answer 4

• int -
• x -
• =, +
• 2,3 "StringLiteral"

, , i.g.

http://java.sun.com/docs/books/jls/second_edition/html/lexical.doc.html

http://java.sun.com/docs/books/jls/second_edition/html/typesValues.doc.html

Answer 5

, . , ,

, ( , , ):

const unsigned int NEGATIVE_TESTER_FOR_32_BIT = 1 < < 31;

const char ALPHABET_PIVOT = 'A' + (('Z' - 'A')/2);

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