ArrayList in java

Question

ArrayList<String> veri1 = new ArrayList<String>();

String[] veri2 = {"Fatih", "Ferhat", "Furkan"};

How to add veri2in veri1as one item? I mean, if I call veri.get(0), it returns veri2.

Answer 1

You should declare your list as a list of string arrays, not a list of strings:

List<String[]> veri1 = new ArrayList<String[]>();
String[] veri2 = {"Fatih", "Ferhat", "Furkan"};

veri1.add(veri2);

Note that, in general, it is better to declare your list as Listinstead ArrayList, as this leaves you with the opportunity to switch to another implementation of the list later.

Answer 2

You should use the List and generics interface (for Java> = 1.5). Depending on what you want to do, you can use this:

String[] veri2 = {"Fatih", "Ferhat", "Furkan"};

List<String> veri1 = new ArrayList<String>();
veri1.addAll(Arrays.asList(veri2)); // Java 6

List<String[]> veri3 = new ArrayList<String[]>();
veri3.add(veri2);

Answer 3

(- fm), ArrayList<String>. :

ArrayList veri1 = new ArrayList();
veri1.add(veri2)

ArrayList<String[]> veri1 = new ArrayList<String[]>();
veri1.add(veri2)

ver1 a List, .

Answer 4

.

veri2 - , veri1 - arraylist , veri1.get(0) , .

Answer 5

, , ArrayList .

String , , :

ArrayList<String[]> list1 = new ArrayList<String[]>();

String :

list1.add(stringArray);

, , :

ArrayList<Object> anythingGoes = new ArrayList<Object>();

- :

anythingGoes.add(stringArray);
anythingGoes.add(myAge);
anythingGoes.add(myName);

Answer 6

, :

import java.util.Arrays;

ArrayList<String> veri1 = new ArrayList<String>();
String[] veri2 = {"Fatih", "Ferhat", "Furkan"};

veri1.addAll(Arrays.asList(veri2);

Answer 7

ArrayList.

ArrayList<String[]> veri1 = new ArrayList<String[]>();
String[] veri2 = {"a", "b", "c"};
veri1.add(veri2);

System.out.println(veri1.size());
for(String[] sArray : veri1)
    for(String s : sArray)
        System.out.println(s);