Polymorphism in java

Question

Is method overloading an example of run-time polymorphism or compile-time polymorphism?

Answer 1

There is no operator overload in Java.

Method overrides allow polymorphism at runtime; method overloading allows compilation time polymorphism.

Read more about this in the tutorial.

see also

• Polymorphism vs Overload and Overload
• Polymorphism: definition in two sentences
• Wikipedia: Polymorphism in OOP

Answer 2

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class A{
    public void doSomething(){
         System.out.println("A method");
    }

    //method overloaded with different arguments-- no polymorphism 
    //or inheritance involved!

    public void doSomething(int i){
         System.out.println("A method with argument");
    }
}

class B extends A{

    //method polymorphically overridden by subclass. 

    public void doSomething(){
         System.out.println("B method");
    }
}

//static type is A, dynamic type is B.
A a = new B();
a.doSomething(); //prints "B method" because polymorphism looks up dynamic type 
                 //for method behavior

Answer 3

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Answer 4

Method overloading is an example of runtime binding. The compiler decides which method should be called only at compile time. So this is compile-time polymorphism, or you can say static binding. But overriding a method is a run-time polymorphism, bcz at runtime, depending on the reference to the object, the method call is allowed.