Pass the value to the Python class via the command line

Question

I have code to pass a variable to a script from the command line. I can pass any value in functionto for an argument var. The problem is that when I put functionin the class, the variable is not read in function. script:

import sys, os

def function(var):
    print var

class function_call(object):
    def __init__(self, sysArgs):
        try:
            self.function = None
            self.args = []
            self.modulePath = sysArgs[0]
            self.moduleDir, tail = os.path.split(self.modulePath)
            self.moduleName, ext = os.path.splitext(tail)
            __import__(self.moduleName)
            self.module = sys.modules[self.moduleName]
            if len(sysArgs) > 1:
                self.functionName = sysArgs[1]
                self.function = self.module.__dict__[self.functionName]
                self.args = sysArgs[2:]
        except Exception, e:
            sys.stderr.write("%s %s\n" % ("PythonCall#__init__", e))

    def execute(self):
        try:
            if self.function:
                self.function(*self.args)
        except Exception, e:
            sys.stderr.write("%s %s\n" % ("PythonCall#execute", e))

if __name__=="__main__":
    function_call(sys.argv).execute()

This works by typing ./function <function> <arg1 arg2 ....>. The problem is that I want to select the function that I want, which is in the class, and not just the function itself. The code I tried is the same, except that function(var):is in the class. I was hoping for some ideas on how to change the class function_callto accept this.

If I want to pass a value Hello, I ran the script as follows: python function_call.py function Hello. Then it prints the variable varas Hello.

, . script , , . python function.py function hello , . python function.py A function hello.

, . - , . _________________________________________________________________________________

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class A:
    def __init__(self):
        self.project = sys.argv[2]
    def run(self, *sysArgs):
        pass
    def funct(self):
        print self.project

class function_call(object):
    def __init__(self, sysArgs):
        try:
            self.function = None
            self.args = []
            self.modulePath = sysArgs[0]
            self.moduleDir, tail = os.path.split(self.modulePath)
            self.moduleName, ext = os.path.splitext(tail)
            __import__(self.moduleName)
            self.module = sys.modules[self.moduleName]
            if len(sysArgs) > 1:
                self.functionName = sysArgs[1]
                self.function = getattr(A(), sysArgs[1])(*sysArgs[2:])
                self.args = sysArgs[2:]
        except Exception, e:
            sys.stderr.write("%s %s\n" % ("PythonCall#__init__", e))

    def execute(self):
        try:
            if self.function:
                self.function(*self.args)
        except Exception, e:
            sys.stderr.write("%s %s\n" % ("PythonCall#execute", e))


if __name__=="__main__":
    function_call(sys.argv).execute()
    inst_A = A()
    inst_A.funct()

.

Answer 1

getattr :

>>> argv = ['function.py', 'run', 'Hello']
>>> class A:
    def run(self, *args):
        print(*args)


>>> getattr(A(), argv[1])(*argv[2:])
Hello

Answer 2

, :

self.function = self.module.__dict__[self.functionName]

- ( @SilentGhost):

self.function = getattr(some_class, self.functionName)

( ) , . some_class , self.function.

, , , classmethod staticmethod, , some_class.function_you_want_to_pick .