Agnostic language The main programming issue

Question

This is a very simple question from the point of view of programming, but since I am in the learning phase, I thought it was better to ask this question and not have a misunderstanding or narrow knowledge of this topic.

So excuse me if I messed it up somehow.

Question

Let's say I class A,B,C and Dnow class Ahave a piece of code that I need to have in class B,C and D, so I am expanding class Aintoclass B, class C, and class D

Now, how can I access the function class Ain other classes, I need to create an object class Aand access the function class Aor how to continue the extension Ain other classes, than I can call the function internally using this parameter.

If possible, I would really appreciate it if anyone could explain this concept with an example code that explains how logic flows.

Note

An example in Java, PHP and .Net would be appreciated.

Answer 1

C D, , B. B A, B A. , B, A. ( , , ), . B A, (base.Foo() ).

: #

public class A
{
     public void Foo() { } 
     public virtual void Baz() { }
}

public class B : A  // B extends A
{
      public void Bar()
      {
          this.Foo();  // Foo comes from A
      }

      public override void Baz() // a new Baz
      {
          base.Baz();  // A Baz
          this.Bar();  // more stuff
      }
}

, , , B A , A ( public) .

: #

 public class B // use A from above
 {
     private A MyA { get; set; }

     public B()
     {
         this.MyA = new A();
     }

     public void Bar()
     {
         this.MyA.Foo();  // call MyA Foo()
     }
 }

Answer 2

( .NET), - :

base.method(argumentlist);

base #

A, A

Answer 3

.

PHP:

parent::example();

: http://www.php.net/manual/en/keyword.parent.php

<?php
class A {
    function example() {
        echo "I am A::example() and provide basic functionality.<br />\n";
    }
}

class B extends A {
    function example() {
        echo "I am B::example() and provide additional functionality.<br />\n";
        parent::example();
    }
}

$b = new B;

// This will call B::example(), which will in turn call A::example().
$b->example();
?>

Answer 4

, , B A, . A B , B , B , , .

, B A , , . , , ; , Java :

super.methodName(arg1, ...);

Answer 5

Java:

public class Aclass
{
    public static void list_examples()
    {
        return("A + B = C");
    }
}
public class Bclass extends Aclass
{
    public static void main(String [] args)
    {
        System.out.println("Example of inheritance "+list_examples);
    }
}

, . , parent:: - , /.

Answer 6

, . "B" , "C" "D" "A" , , . , "Huffy" "BrandNames" , "Huffy" , "BrandNames" . "Huffy" "" , "BrandNames" . , ( Java) , . "B" "A" , , "C" "A" "B" , "C" .