Using the functions of PHP Image and GD, you can use the following method to finally output the php image
imagepng($image);
Sometimes for some reason the image may not be displayed, as a rule, the error is not with the image, but with the actual php functions that are not executed successfully. However, this leads to the return of a blank image that does not help me.
I want to know if there is a way to detect an empty or invalid image and create a new image, write errors to a new image using imagestring (), and then display this new (debug) image.
For example, a successfully displayed image without errors:
$image = imagecreate(256, 256);
imagecolortransparent($image, $BLUE);
imagefilledrectangle($image, 0, 0, 256, 256, $BLUE);
imageline($image, 0, 0, 0, 255, $Black);
imageline($image, 0, 0, 255, 0, $Black);
imageline($image, 255, 0, 255, 255, $Black);
imageline($image, 0, 255, 255, 255, $Black);
imagestring($image, 1, 10, 10, "I am an image!", $Black);
imagepng($image);
imagedestroy($image);
php script, , PHP , ...
$image = imagecreate(256, 256);
imagecolortransparent($image, $BLUE);
imagefilledrectangle($image, 0, 0, 256, 256, $BLUE);
imageline($image, 0, 0, 0, 255, $Black);
imageline($image, 0, 0, 255, 0, $Black);
imageline($image, 255, 0, 255, 255, $Black);
imageline($image, 0, 255, 255, 255, $Black);
imagestring($image, 1, 10, 10, "I am an image!", $Black);
non_existant_function()
imagepng($image);
imagedestroy($image);
, , , ! , .