R, taking into account the appearance of similar rows of the data frame

Question

I have data in the following DF format (this is just a simplified version):

eval.num, eval.count, fitness, fitness.mean, green.h.0, green.v.0, offset.0 random
1         1           1500     1500          100        120        40       232342
2         2           1000     1250          100        120        40       11843
3         3           1250     1250          100        120        40       981340234
4         4           1000     1187.5        100        120        40       4363453
5         1           2000     2000          200        100        40       345902
6         1           3000     3000          150        90         10       943
7         1           2000     2000          90         90         100      9304358
8         2           1800     1900          90         90         100      284333

However, the eval.count column is incorrect and I need to fix it. It should report the number of lines with the same values ​​for (green.h.0, green.v.0 and offset.0), only by looking at the previous lines.

The above example uses expected values, but assumes they are incorrect.

How to add a new column (say, "count") that will count all previous rows that have the same values ​​for the specified variables?

I got help on a similar problem by simply selecting all rows with the same values ​​for the specified columns, so I assumed that I could just write a loop around this, but it seems inefficient.

Answer 1

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> data <- rep(sample(1000, 5),
              sample(5, 5))
> head(data)
[1] 435 435 435 278 278 278

rle :

> sequence(rle(data)$lengths)
[1] 1 2 3 1 2 3 4 5 1 2 3 4 1 2 1

:

> head(cbind(data, sequence(rle(data)$lengths)))
[1,]  435 1
[2,]  435 2
[3,]  435 3
[4,]  278 1
[5,]  278 2
[6,]  278 3

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Answer 2

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cmpfun2 <- function(r) {
    count <- 0
    if (r[1] > 1)
    {
        for (row in 1:(r[1]-1))
        {
            if(all(r[27:51] == DF[row,27:51,drop=FALSE]))  # compare to row bind
            {
                count <- count + 1
            }
        }
    }
    return (count)
}
brows <- apply(DF[], 1, cmpfun2)
print(brows)

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Answer 3

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checkIt <- function(bind) {

    print(bind)

    cmpfun <- function(r) {all(r == heeds.data[bind,23:47,drop=FALSE])}
    brows <- apply(heeds.data[,23:47], 1, cmpfun)

    #print(heeds.data[brows,c("eval.num","fitness","green.h.1","green.h.2","green.v.5")])
    print(nrow(heeds.data[brows,c("eval.num","fitness","green.h.1","green.h.2","green.v.5")]))
}

, heeds.data - , , , ( ). , 23:47 - , .

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, !