How to change int to binary. on python 2.5

Question

print 077777#how can i get binary

I am using python2.5

Answer 1

The simplest (not the fastest!) Way to get a binary string for an int in Python 2.5:

def dobin(n):
  digs = []
  s = ''
  if n<0:
    s = '-'
    n = -n
  while True:
    digs.append(str(n % 2))
    n /= 2
    if not n: break
  if s: digs.append(s)
  digs.reverse()
  return ''.join(digs)

Are you looking for speed or for clarity?

Answer 2

Make a map of hexadecimal characters for binary sequences, then do a number through (note: only works for non-negative numbers):

def bin(value):
    binmap = {'0': '0000', '1': '0001', ..., 'f': '1111'}
    return ''.join(binmap[x] for x in ('%x' % (value,))).lstrip('0') or '0'

Answer 3

ActiveState Code, :

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Python 2.6 , .

:

print '{0:b}'.format(077777)

Answer 4

n = 1234

"".join([["0", "1"][(n >> i) & 1] for i in reversed(range(n.__sizeof__()))])

, sizeof correct.you .

"".join([["0", "1"][(n>>i)&1] for i in range(log(n,2)+1)])