What "returns $ container & # 8594; {$ resource};" I mean

Question

What do marriages mean and where to read next

return $container->{$resource};

Answer 1

Two possibilities:

• variable variable .

  $ resource = "score"; // dynamically set the name

  return $ container → {$ resource}; // same as return $ container-> score;

• typo / novice error

The programmer should have entered:

return $container->resource;  // returns resource public member variable

Answer 2

Brackets must use variable variables. This facilitates the distinction between:

// gets the value of the "resource" member from the container object
$container->resource;

and

// gets the value of the "foo" member from the container object
$resource = 'foo';
$container->$resource;

You can read more here: http://php.net/manual/en/language.variables.variable.php