Algorithm for finding all cycles in a directed graph in C ++ using the Adjacency matrix

Question

In the presence of a graph adjacency matrix (for example, g [] []), the graph is directed. It is required to find the counter of all graphic cycles (if any) and print them.

I tried to write this algorithm in Java, sometimes it works correctly. If the graph has complex loops, the algorithm returns crazy loops. Please see my code and help solve this problem.

public static final int k = 6;

public static int g[][] = { { 0, 1, 0, 0, 0, 0 },
                            { 1, 0, 1, 0, 0, 0 },
                            { 0, 0, 0, 1, 0, 0 },
                            { 0, 0, 0, 0, 1, 0 },
                            { 0, 0, 1, 0, 0, 0 },
                            { 0, 0, 0, 0, 0, 0 } };

public static Vector stack = new Vector();

public static void printStack() {
    System.out.print("stack is: { ");
    for (int i = 0; i < stack.size(); i++) {
        System.out.print(stack.get(i) + " ");
    }
    System.out.println("};");

}

public static boolean checkCycle() {
    boolean res = false;

    for (int i = 0; i < stack.size() - 1; i++) {
        if (stack.get(i).equals(stack.lastElement())) {
            res = true;
            break;
        }

    }
    return res;
}

public static boolean go_to_line(int line) {
    boolean res = false;
    for (int i = 0; i < k; i++) {
        if (g[line][i] == 1) {
            stack.add(i);
            if (checkCycle() == true) {
                System.out.println("Cycle found!");
                res = true;
            } else {
                res = go_to_line(i);
            }
        }
    }

    return res;
}

public static int cycles_count() {
    int res = 0;

    for (int i = 0; i < k; i++) {
        if (g[i][i] == 1) {
            System.out.println("Knot detected at item {" + i + "}!");
            res++;
        }

        for (int j = i + 1; j < k; j++) {
            if (g[j][i] == 1) {
                stack.add(j);
                stack.add(i);

                if (go_to_line(i) == true) {
                    res++;

                    System.out.print("Final ");
                    printStack();
                    stack.removeAllElements();
                }
            }
        }
    }

    return res;
}

Answer 1

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Answer 2

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