Global variable in javascript?

Question

I have this code:

    $(".link").each(function() {
            group += 1;
            text += 1;
            var links = [];
            links[group] = [];

            links[group][text] = $(this).val();
        }
    });

    var jsonLinks = $.toJSON(links);

after it loops through each .link, it will exit each loop and encode the "links" of the array to json. but the array "references" are a local variable within each loop. how can i make it global outside the loop?

Answer 1

Define linksoutside the loop:

var links = [];
$(".link").each(function() {
  group += 1;
  text += 1;
  links[group] = [];
  links[group][text] = $(this).val();
});
var jsonLinks = $.toJSON(links);

I should also point out that this does not make much sense, because you get element 7, for example, being an array with one element (with index 7). Is this really what you want?

I think what you want is an array of values. If so, why not use it map()?

var links = $(".link").map(function(i, val) {
  return $(val).val();
});

Answer 2

.

var links = [];

$(".link").each(function() {
        group += 1;
        text += 1;            
        links[group] = [];

        links[group][text] = $(this).val();
    }
});

var jsonLinks = $.toJSON(links);

Answer 3

:

var links = [];
$(".link").each(function() {
        group += 1;
        text += 1;
        links[group] = [];
        links[group][text] = $(this).val();
    }
});

var jsonLinks = $.toJSON(links);

'var':

$(".link").each(function() {
        group += 1;
        text += 1;
        links = [];
        links[group] = [];
        links[group][text] = $(this).val();
    }
});

var jsonLinks = $.toJSON(links);

Answer 4

:

{    
    var links = [];
    $(".link").each(function() {
            group += 1;
            text += 1;

            links[group] = [];

            links[group][text] = $(this).val();
        }
    });

    var jsonLinks = $.toJSON(links);
}

Answer 5

,

a) ( )

b)

$(".link").each(function() {
            group += 1;
            text += 1;
            window.links = [];
            links[group] = [];

            links[group][text] = $(this).val();
        }
    });

    var jsonLinks = $.toJSON(links);

c) var

$(".link").each(function() {
            group += 1;
            text += 1;
            links = [];
            links[group] = [];

            links[group][text] = $(this).val();
        }
    });

    var jsonLinks = $.toJSON(links);

Answer 6

JavaScript

• Global: - var

• : , .

,

 function getJSONLinks()
 {
      var links = [];
      $(".link").each(function() {
        group += 1;
        text += 1;
        links[group] = [];
        links[group][text] = $(this).val();
       }
     });
     return $.toJSON(links);
 }