Counting in awk

Question

#!/bin/sh
find ${*-.} -type f -print | xargs file | 
awk '{
$1=NULL;
t[$0]++;
}
end {
for (i in t) printf("%d\t%s\n", t[i], i);
}' | sort -nr

The first line of search. But the awk part does not work. I expect the number of file types to be sorted in descending order.

Answer 1

awk is case sensitive - end must be END

Answer 2

Use END, not END.

Answer 3

Try adding a space between the tick and {:

awk ' {

Some AWK versions need this.