The math power operator is not working properly

Question

short sho1, sho2;
printf("Enter two shorts.\n");
scanf("%hd %hd", &sho1, &sho2);
printf("%hd^%hd is %hd.\n", sho1, sho2, sho1^sho2);

When I enter "2 2", I get this output:

2 ^ 2 is 0.

How did it happen? I use the MinGW GCC compiler in Eclipse, if that matters.

Answer 1

^is not a mathematical power operator in C, it is a bitwise exclusive-OR operator . You probably need a pow function that takes two doubles.

Answer 2

You are not using the operator that you think you are using.

^- bitwise operator XOR .

You are looking for pow function .

Prototype: double pow (double b, double p);

: math.h(C) cmath (++)

: b p .

, C ++.

Answer 3

^ ; XOR. pow, math.h. :

pow(2.0, 2.0)

4.0 ( , ).

, pow double, %g:

printf("%hd^%hd is %g.\n", sho1, sho2, pow((double)sho1, (double)sho2));

Answer 4

C - ^ "", XOR ( )

Answer 5

You can use the pow () function in C.

pow(base, exponent);

This is in the math.h header file.

Answer 6

In c ^, is exclusive or operator. You must use a pow  function to make permissions .

pow(2,2)