WPF: adding button columns to Datagrid

Question

Hi, how can I program the Button column in a Datagrid. I want to do this using the code in the codebehind file.

I also want to selectively enable or disable this button based on the entry (if the status is open, then Enable again disable this button). Here, Status is a column in a DataSource.

Thanks Abi

Answer 1

The viky-related answer summarizes the idea of ​​adding a button column from a source. I put together a short example that also shows the second part of your question, which is how to enable / disable a button based on data in the grid. I used DataGrid in 4.0, but the toolbox with 3.5 should also be great.

First, I add one Name column from XAML. This is optional, but just shows that you can combine the XAML and C # add-ons with the grid. Note that I call the grid here, so I have a way to reference it in a partial C # class.

<Window x:Class="WpfApplication2.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Data Grid Populated in XAML and C#">
    <Grid>
        <DataGrid x:Name="_gridControl" IsReadOnly="True" AutoGenerateColumns="False">
            <DataGrid.Columns>
                <DataGridTextColumn Header="Name" Width="*" Binding="{Binding Name}"/>
            </DataGrid.Columns>
        </DataGrid>
    </Grid>
</Window>

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public partial class MainWindow : Window
{
    public MainWindow()
    {
        InitializeComponent();

        var buttonTemplate = new FrameworkElementFactory(typeof(Button));
        buttonTemplate.SetBinding(Button.ContentProperty, new Binding("Name"));
        buttonTemplate.SetBinding(Button.IsEnabledProperty, new Binding("Status")
        {
            Converter = new StatusToEnabledConverter()
        });
        buttonTemplate.AddHandler(
            Button.ClickEvent, 
            new RoutedEventHandler((o, e) => MessageBox.Show("hi"))
        );
        this._gridControl.Columns.Add(
            new DataGridTemplateColumn()
            {
                Header = "Close Button",
                CellTemplate = new DataTemplate() { VisualTree = buttonTemplate }
            }
        );

        this._gridControl.ItemsSource = new object[]
        {
            new { Name = "First Item", Status = "Open" },
            new { Name = "Second Item", Status = "Open" },
            new { Name = "Third Item", Status = "Closed" },
            new { Name = "Fourth Item", Status = "Closed" },
            new { Name = "Fifth Item", Status = "Open" }
        };
    }
}

public class StatusToEnabledConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter,
        CultureInfo culture)
    {
        return "Open".Equals(value);
    }

    public object ConvertBack(object value, Type targetType, object parameter,
        CultureInfo culture)
    {
        throw new System.NotImplementedException();
    }
}

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, !

Answer 2

Xaml:

<DataGridTemplateColumn>
                        <DataGridTemplateColumn.CellTemplate>
                            <DataTemplate>
                                <Button Click="Details">Details</Button>
                            </DataTemplate>
                        </DataGridTemplateColumn.CellTemplate>
                    </DataGridTemplateColumn>

       private IEnumerable<DataGridRow> GetDataGridRowsForButtons(DataGrid grid)
    { //IQueryable 
        var itemsSource = grid.ItemsSource as IEnumerable;
        if (null == itemsSource) yield return null;
        foreach (var item in itemsSource)
        {
            var row = grid.ItemContainerGenerator.ContainerFromItem(item) as DataGridRow;
            if (null != row & row.IsSelected) yield return row;
        }
    }

    void Details(object sender, RoutedEventArgs e)
    {

        for (var vis = sender as Visual; vis != null; vis = VisualTreeHelper.GetParent(vis) as Visual)
            if (vis is DataGridRow)
            {
               // var row = (DataGrid)vis;

                var rows = GetDataGridRowsForButtons(dgv_Students);
                string id;
                foreach (DataGridRow dr in rows)
                {
                    id = (dr.Item as tbl_student).Identification_code;
                    MessageBox.Show(id);
                }
                break;
            }
    }

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