How to match decimal letter and space in vim?

Question

I need to change

1  A
2  B
3  C
4  D

to

A
B
C
D

which means that the decimal letter at the beginning of each line and the next one or more spaces should be removed.

I am only familiar with Reqex in Perl, so I am trying to use:% s / ^ \ d \ s + // to solve my problem, but this will not work. so can any of you tell me how to get the job done with vim?

thanks.

Answer 1

Vim requires a backslash for +, so try

:%s/^\d\s\+//

Answer 2

One way is to use a global command with a find and replace command:

:g/^[0-9]  */s//

He is looking for the sequence:

• beginning of line ^
• numeral [0-9]
• space <space>
• zero or more spaces <space>*

(s//).

" ", , ( ).

Answer 3

:%s/^[0-9]  *//

Answer 4

:%s/^\d\s\+//

, vim - - , perl. + +.

, .

:%s/\v^\d\s+//

.

:help magic

Answer 5

Visual Block (Ctrl + V), , "x", . ( ).

Answer 6

Perl , :

:%!perl -pe 's/^\d\s+//'

Vim will write the file to a temporary file, run the given Perl script and reload the file into the editing buffer.

Answer 7

Reset the plus sign:

:%s/^\d\s\+//

Answer 8

If in a column like this, you can go into the visual mode of the column by clicking:

esc ctrl+q

then you can highlight what you want to delete