How to prevent overload?

Question

Is it possible to prevent overloading user-defined functions in C ++? Suppose I have a function:

void foo(int , int);

Can I prevent overloading foo, and if so, how? If possible, can this be expanded to prevent overriding methods through inheritance?

Answer 1

In a word: no. You cannot prohibit overloading foowith another signature somewhere else, and you cannot prevent overriding virtual functions.

In the C ++ world, you need to trust people writing code that ends in your program.

Answer 2

Section 13.1.1 through 13.1.3 of the standard describes the types of functions that cannot be overloaded:

:

• , , .
• - , (9.4).

: 8.3.5, , , :

• , typedef, . , (7.1.3).
• , * [], . , (8.3.5). (8.3.4).
• , , , - , . , (8.3.5).
• , / , . , - , , .
• , , .

, .

Answer 3

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Answer 4

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Answer 5

, UncleBens, , , , . , . ( , ).

, , . . .

Answer 6

- C:

extern "C" void foo(int , int);

This works because with C-binding, the names are not distorted, so you cannot overload (which uses the encoding of argument types in the character name).

Obviously, this will not apply to member functions.