Java strings storing byte arrays

Question

I want to keep an array of bytes wrapped in a String object. Here is the script

• The user enters a password.
• The bytes of this password are obtained using the getBytes () String method.
• These bytes are encrypted using the java crypo package.
• These bytes are then converted to String using the new String constructor (bytes [])
• This string is stored or otherwise transmitted (does not change)
• The bytes of this string are received, and they differ from the encoded bytes.

Here is a snippet of code describing what I'm talking about.

String s = "test123";
byte[] a = s.getBytes();
byte[] b = env.encrypt(a);
String t = new String(b);
byte[] c = t.getBytes();
byte[] d = env.decrypt(c);

Where env.encrypt () and env.decrypt () do encryption and decryption. The problem I am facing is that array b has length 8 and array c has length 16. I think they will be equal. What's going on here? I tried to change the code as shown below.

String s = "test123";
Charset charset = Charset.getDefaultCharset();
byte[] a = s.getBytes(charset);
byte[] b = env.encrypt(a);
String t = new String(b, charset);
byte[] c = t.getBytes(charset);
byte[] d = env.decrypt(c);

.

?

Answer 1

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Answer 2

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String s = "test123";
byte[] a = s.getBytes();

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byte[] b = env.encrypt(a);

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byte[] c = t.getBytes();

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byte[] d = env.decrypt(c);

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  byte[] cypherBytes = env.encrypt(getBytes(plainText));
  StringBuffer cypherText = new StringBuffer(cypherBytes.length * 2);
  for (byte b : cypherBytes) {
    String hex = String.format("%02X", b); //$NON-NLS-1$
    cypherText.append(hex);
  }
  return cypherText.toString();
  

:

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:

String s = "tést123";
byte[] a = s.getBytes();
byte[] b = env.encrypt(a);

String s = "tést123";
byte[] a = s.getBytes("UTF-8");
byte[] b = env.encrypt(a);

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Answer 3

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Answer 4

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Answer 5

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Answer 6

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Answer 7

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