Good morning,
I have been a PHP programmer for quite some time, but I felt the need to move more towards Python and which is better than playing with Django.
During the process, I came to a breakpoint where I know that there is a simple solution, but I just donβt see it - How to display many relationships in a Django template?
My Django Model: (most of the fields removed)
class Category(models.Model):
name = models.CharField(max_length=125)
slug = models.SlugField()
categories = models.ManyToManyField(Category, blank=True, null=True)
class Recipe(models.Model):
title = models.CharField('Title', max_length=250)
slug = models.SlugField()
class Photo(models.Model):
recipe = models.ForeignKey(Recipe)
image = models.ImageField(upload_to="images/recipes", blank=True)
So, there are the main models that I use in my application called "recipes".
With that said, there are two questions I'm looking for answers to:
- How can I show categories for a recipe on the details page?
- How do I display an image for a recipe on the details page?
If I enter the Python shell and enter the following, I get the result:
>>> photos = Photo.objects.filter(recipe=1)
>>> photos
[<Photo: Awesome Pasta>]
>>> for photo in photos:
... print "Photo: %s" % photo.logo
...
Photo: images/recipes/2550298482_46729d51af__.jpg
- , " :" photo.image "."
{% for photo in photos %}
{% photo.image %}
{% endfor %}
, , - , ?
Page View.py snippet:
def details(request, slug='0'):
p = get_object_or_404(Recipe, slug=slug)
photos = Photo.objects.filter(recipe=1)
return render_to_response('recipes/recipes_detail.html', {'p': p, 'photos': photos})
, , , !
UPDATE: Recipes.