Running crontab with user input

Question

i created crontab that will run the bash script test.sh. This test.sh file requires some input from the user and saves the user input into a variable. How can I guarantee that user input will be stored in a variable in test.sh, and when crontab runs the script, can I get the output I want?

for example, I have 2 files, file1.sh and file2.sh. I put file2.sh in file 1.sh. Then run file1.sh, enter user input and save it somewhere. crontab will run file2.sh and extract the value from the "stored variable". anyway for this?

Answer 1

If the input is read from the script stdin, just redirect the input from the file (using the script wrapper).

#! /bin/sh
test.sh < data.in

If this does not work for you (i.e. you have a script invoking some kind of interactive shell such as telnet, you can use it Expectto automate the interaction.

Answer 2

• file1.sh receives user input and writes it to /etc/file2.dat
• file2.shreads /etc/file2.datand does everything he needs

Answer 3

. :

, , cron?

, ?