First of all, this is my third question about web services, and I am very grateful to guyz for helping me, but still something is missing, what’s wrong is the code that I got already from my question
Set oXmlHTTP = CreateObject("Microsoft.XMLHTTP")
oXmlHTTP.Open "POST", "http://www.oursite.com/WebServices/ourService.asmx?WSDL", False
oXmlHTTP.setRequestHeader "Content-Type", "application/soap+xml; charset=utf-8"
oXmlHTTP.setRequestHeader "SOAPAction", "http://ourNameSpace/ourFunction"
SOAPRequest = _
"<?xml version=""1.0"" encoding=""utf-8""?>" &_
"<soap12:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap12=""http://www.w3.org/2003/05/soap-envelope"">" &_
"<soap12:Body>" &_
"<ourFunction xmlns=""http://ourNameSpace/"">" &_
"<var1>" & Session("userid") & "</var1>" &_
"<var2>" & Session("internetid") & "</var2>" &_
"</ourFunction>" &_
"</soap12:Body>" &_
"</soap12:Envelope>"
oXmlHTTP.send SOAPRequest
Now my web service link
http://buergerserviceschul.niedersachsen.de/modules/id/public/webservice/V4_00/rpc_lit/?wsdl
When I provide a call to a web service, providing all the details and all the necessary materials, still I can not get any data from this procedure, which is disappointing. I mean that I do not get anything, I get empty answers, and if I use the old method, which I was asked not to implement, which was used by the soap client i.e.
Set oSOAP = Server.CreateObject("MSSOAP.SoapClient30")
oSOAP.ClientProperty("ServerHTTPRequest") = True
now this way I get the session id, but again I couldn’t move on even if you use this procedure, so guyz I am stuck in this problem
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