How can I bind a byte array in Java?

Question

Is there a way to bind a byte array in java, so it never moves / compacts?

I am working on an application that should have zero GCs at runtime, and I want to use primitive byte arrays that are bound to a memory display area. Is there any way to do this or hack my way to it?

Answer 1

You can use ByteBuffer / allocateDirect (). This creates a byte buffer that is in the "c" space and does not use heap, so it will not move and can be used effectively with JNI calls.

Answer 2

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EDIT :

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/** Byte arrays that you absolutely have to keep. */
public class KeepForever {
    /** Note that I make no claims about thread safety in this simple example. */
    public static byte [] keepMe = new byte[100];
};

// Much later in example code ....

/** This should always succeed.  No worries about garbage collection. */
public void setMe(int index, byte newByte) {
    // Admittedly, this defeats several principles of OOD but it makes 
    // the point about the syntax.
    KeepForever.keepMe[index] = newByte;
}

Answer 3

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Answer 4

. https://highlyscalable.wordpress.com/2012/02/02/direct-memory-access-in-java/. JVM, , , .