Find the folder for files like "/*tmp*.log" in Python

Question

As the name says, I use Linux, and a folder can contain more than one file, I want its name to contain *tmp*.log( *means something, of course!). Just like what I use on the Linux command line.

Answer 1

Use the module glob.

>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']

Answer 2

The answer to glob is simpler, but for completeness: you can also use os.listdir and regex check:

import os
import re
dirEntries = os.listdir(path/to/dir)
for entry in dirEntries:
  if re.match(".*tmp.*\.log", entry):
    print entry

Answer 3

, .

, . . , , , , .. , , . , , ( ) , , .

, , . $MY_APP_HOME/dat. my_config_, combo, -. : ( ) my_config_11_fast_but_sloppy.txt, my_config_100_balanced.txt, my_config_3_thorough_but_slow.txt, ( ): Thorough But Slow, Fast But Sloppy, Balanced.

,

The MyConfiguration class below does all the work in only a few lines of code (significantly less than what I needed to explain the purpose :-), and it can be used as follows:

# populate my_config combobox
self.my_config = MyConfiguration()
self.gui.my_config.addItems(self.my_config.get_items())

# get selected file path
index = self.gui.my_config.currentIndex()
self.config_file = self.my_config.get_file_path_by_index(index);

Here is the MyConfiguration class:

import os, re

class MyConfiguration:
    def __init__(self):
        # determine directory that contains configuration files
        self.__config_dir = '';
        env_name = 'MY_APP_HOME'
        if env_name in os.environ:
            self.__config_dir = os.environ[env_name] + '/dat/';
        else:
            raise Exception(env_name + ' environment variable is not set.')
        # prepare regular expression
        regex = re.compile("^(?P<file_name>my_config_(?P<index>\d+?)_(?P<desc>.*?)[.]txt?)$",re.MULTILINE)
        # get the list of all files in the directory
        file_names = os.listdir(self.__config_dir)
        # find all files that are our parameters files and parse them into a list of tuples: (file name, index, item_text)
        self.__items = regex.findall("\n".join(file_names))
        # sort by index as an integer
        self.__items.sort(key=lambda x: int(x[1]))

    def get_items(self):
        items = []
        for item in self.__items:
            items.append( self.__format_item_text(item[2]))
        return items

    def get_file_path_by_index(self, index):
        return self.__config_dir + self.__items[index][0]

    def __format_item_text(self, text):
        return text.replace("_", " ").title();