How to create a subset of words for anagram (php) application?

Question

I created an anagram creation application by creating an anagram field in my database with a lowercase alphanumeric string.

For example, suction becomes cinostu, ear becomes aer, etc.

Now I want to create auxiliary words from the desired source anagram.

Example. How would you take a subset of the words from the search for "arrest", that is, "rest" and "stare".

Answer 1

Hey Bork. tried to adapt your code to PHP, and I have the following:

$LetterCount = array ( "a" = > 1, "b" = > 1, "c" = > 1, "d" = > 1, "e" = > 0, "f" = > 1, "g" = > 1, "h" = > 1, "i" = > 1, "j" = > 1, "k" = > 1, "l" = > 1, "m" = > 1, n "= > 1," o "= > 1," p "= > 1," q "= > 1," r "= > 1," s "= > 1," t "= > 1, u "= > 1," v "= > 1," w "= > 1," x "= > 1," y "= > 1," z "= > 1);

$AsciiCodeLowerCaseA = 97;

for ($j = 1; $j < strlen($string); $j++) {
  $CurrentLetter = $string[$j];
  $AsciiCode = ord($CurrentLetter);
  $AlphabetPos = $AsciiCode - $AsciiCodeLowerCaseA + 1;
      $LetterCount[$AlphabetPos] = $LetterCount[$AlphabetPos] + 1;
}

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Answer 2

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Answer 3

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Answer 4

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Answer 5

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SELECT Word FROM Dictionary WHERE NOT (
  (a >= 1) OR (b >= 1) OR (c >= 2) ... OR (z >= 1)
)

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UPDATE -

- ASP (VBScript), PHP , .

Const AsciiCodeLowerCaseA = 97
InputWord = "Carrots"
LowerCaseInputWord = LCase(InputWord)

Dim LetterCount(26)

for i = 1 to 26
  LetterCount(i) = 1
next

for j = 1 to Len(InputWord)
  CurrentLetter = Mid(InputWord, j, 1)
  AsciiCode = Chr(CurrentLetter)
  AlphabetPos = AsciiCode - AsciiCodeLowerCaseA + 1
  LetterCount(AlphabetPos) = LetterCount(AlphabetPos) + 1
next

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Answer 6

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$LetterCount = array ( "a" = > 1, "b" = > 1, "c" = > 1, "d" = > 1, "e" = > 0, "f" = > 1, "g" = > 1, "h" = > 1, "i" = > 1, "j" = > 1, "k" = > 1, "l" = > 1, "m" = > 1, n "= > 1," o "= > 1," p "= > 1," q "= > 1," r "= > 1," s "= > 1," t "= > 1, u "= > 1," v "= > 1," w "= > 1," x "= > 1," y "= > 1," z "= > 1);

$AsciiCodeLowerCaseA = 97;

for ($j = **0**; $j < strlen($string); $j++) {
  $CurrentLetter = $string[$j];
  $AsciiCode = ord($CurrentLetter);
  $AlphabetPos = **chr($AsciiCode - $AsciiCodeLowerCaseA + 1);**
  $LetterCount[$AlphabetPos] = $LetterCount[$AlphabetPos] + 1;
}

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for($j = 0; $j < strlen($string); $j++) {
$LetterCount[$string[$j]]++;
}