Many java processes on jvm?

Question

If I want to run several processes in one jvm without synchronization (I don't care that several things work at the same time ... I just want to avoid restarting jvm), what is the best solution?

Starting one thread and connecting to wait until it dies, and then create another thread to perform another task?

Answer 1

Reminds me of JSR 121 Isolates . This specification is complete, but I'm not sure if anything ever happened to the implementation of this stuff. There is a continuation of JSR 284 .

Answer 2

Ant Java Java JVM - , fork false ( ). .

Answer 3

/ . , , . , .

Java, , . JVM. , JVM , , JVM. , , JVM.

Answer 4

, , (.. jar , java) java-, jvm . BeanShell, , .

:

java -cp bsh-2.0b4.jar;yourapp.jar bsh.Console

,

bsh % com.domain.prog.Mainclass.main( new String[] { } );

Answer 5

Runtime.exec Process, . Process , , , () .

Answer 6

JVM; JVM ( , ). , JVM.

Answer 7

, , , . , . , Runnables. run(), , , , start():

public class T1 extends Thread {
   public void run () { .. do something useful .. }
}

public class T2 extends Thread { ... yadda yadda }

public static void main (String args[] )
{
 new T1().start();
 new T2().start();
}

Answer 8

A.) / , , , , Classloaders/Reflection (String [] args) , .

Answer 9

You do not even need threads to sequentially run a number of other Java programs:

public class RunPrograms {

   public void main(args) {
      <for each applicationClass and args> {
        try {
           applicationClass.main(args)
        } catch Exception e {
           // if you want the entire set to die if one dies, rethrow (or don't catch)
           // otherwise somehow log the error and continue
        }
      }
   }
}

You will have problems if any of the programs causes System.exit(), but this will be true for any system using one jvm.