Subquery to return the last record for each parent id

Question

I have a parent table with records for documents, and I have a history table that records an audit record each time a user accesses one of the documents.

I am writing a search query to return a list of documents (filtered by various criteria) with the last user ID in order to access each document returned in the result set.

So for

    DOCUMENTS
    ID | NAME
    1  | Document 1
    2  | Document 2
    3  | Document 3
    4  | Document 4
    5  | Document 5

    HISTORY
    DOC_ID | USER_ID | TIMESTAMP
    1      | 12345   | TODAY
    1      | 11111   | IN THE PAST
    1      | 11111   | IN THE PAST
    1      | 12345   | IN THE PAST
    2      | 11111   | TODAY
    2      | 12345   | IN THE PAST
    3      | 12345   | IN THE PAST

I would like to receive a refund from my search, for example

    ID | NAME       | LAST_USER_ID
    1  | Document 1 | 12345
    2  | Document 2 | 11111
    3  | Document 3 | 12345
    4  | Document 4 | 
    5  | Document 5 | 

Is it easy to do this with a single SQL query and a join between two tables?

Answer 1

, , ( MS SQL Server) DB2 ( SQL) " ":

SELECT d.id, d.name, h.last_user_id
    FROM Documents d LEFT JOIN
         (SELECT r.doc_id AS id, user_id AS last_user_id
              FROM History r JOIN
                   (SELECT doc_id, MAX("timestamp") AS "timestamp"
                        FROM History
                        GROUP BY doc_id
                   ) AS l
                   ON  r."timestamp" = l."timestamp"
                   AND r.doc_id      = l.doc_id
         ) AS h
         ON d.id = h.id

, "TIMESTAMP" - , .

, Andy , (?) .

Answer 2

"HAVING MAX (TIMESTAMP)" SQL Server - , "max (TIMESTAMP) > 2009-03-05" -, . ( - ...)

- - , 2 ( , ):

select
    d.ID,
    d.NAME,
    h."USER_ID" as "LAST_USER_ID"
from Documents d
left join History h
    on d.ID = h.DOC_ID
    and h."TIMESTAMP" =
    (
        select max("TIMESTAMP")
        from "HISTORY"
        where "DOC_ID" = d.ID
    )

Answer 3

, , , . , , NVL().

select a.ID, a.NAME,
(select x.user_id
 from HISTORY x
 where x.doc_id = a.id
   and x.timestamp = (select max(x1.timestamp)
                      from HISTORY x1
                      where x1.doc_id = x.doc_id)) as LAST_USER_ID
from DOCUMENTS a
where <your criteria here>

Answer 4

, :

SELECT ID, Name,  b.USER_ID as LAST_USER_ID
FROM DOCUMENTS a LEFT JOIN
    ( SELECT DOC_ID, USER_ID 
          FROM HISTORY
              GROUP BY DOC_ID, USER_ID
              HAVING MAX( TIMESTAMP )) as b
    ON a.ID = b.DOC_ID

:

SELECT ID, Name,  b.USER_ID as LAST_USER_ID
FROM DOCUMENTS a 
  LEFT JOIN HISTORY b ON a.ID = b.DOC_ID
GROUP BY DOC_ID, USER_ID
HAVING MAX( TIMESTAMP )

Answer 5

Select ID, Name, User_ID
From Documents Left Outer Join
History a on ID = DOC_ID
Where ( TimeStamp = ( Select Max(TimeStamp)
                      From History b
                      Where a.DOC_ID = b.DOC_ID ) OR
        TimeStamp Is NULL )  /* this accomodates the Left */