killall -r -9 .sends a signal 9to all processes matching the regular expression .(i.e., it kills all processes). As he kills himself, the question arises: will he kill himself last, so he will do what is documented, or maybe it will kill himself before finishing the job, leaving the processes alive.
After @David's answer, this means that if you run it killalltwice, it will have less chance of working than if you run it once, because everyone killallcan kill the other before he finishes work.
Is this a new paradox similar to the stop problem?
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