In C #, I can do this.
[Flags]
enum BeerProperty
{
Bold = 1,
Refreshing = 2
}
static void Taste(BeerProperty beer)
{
if (beer == (BeerProperty.Bold | BeerProperty.Refreshing))
{
Debug.WriteLine("I can't qutie put my finger on...");
}
}
static void Main(string[] args)
{
var tickBeer = BeerProperty.Bold | BeerProperty.Refreshing;
Taste(tickBeer);
}
In Kotlin it seems that I can’t “OR” two flags. What is the Kotlin method? Using a list of enumeration variables?
enum class BeerProperty(value:Int)
{
Bold(1),
Refreshing(2)
}
fun taste(beer:BeerProperty)
{
if(beer == (BeerProperty.Bold | BeerProperty.Refreshing))
{
print("I can't qutie put my finger on...");
}
}
fun main(args: Array<String>)
{
val tickBeer = BeerProperty.Bold | BeerProperty.Refreshing;
taste(tickBeer);
}
Added: Thank you for the answer (which I still can not mark as an answer, due to the time limit). I changed the code as shown below and achieved what I wanted.
fun taste(beer: EnumSet<BeerProperty>)
{
if(beer.contains(BeerProperty.Bold) && beer.contains(BeerProperty.Refreshing))
{
print("I can't qutie put my finger on...");
}
}
fun main(args: Array<String>)
{
val tickBeer = EnumSet.of(BeerProperty.Bold, BeerProperty.Refreshing);
taste(tickBeer);
}
source
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