Matlab fft2 (2D), giving variable values ​​compared to multiple fft (1D), performed on rows and columns

Question

function [output1, output2] = fft2D(input)

   output1 = input';
   output1 = fft(output1);
   output1 = output1';
   output1 = fft(output1);

   output2 = fft2(input);
end

So, I calculate on output2 a 2D FFT inputand on output1 the same 2D FFT input. fft()applied to a two-dimensional FFT matrix over column vectors. So above I apply it row by row, and then column by column.

However, for a random matrix

 [1   1   4   1; 
  12  13  124 1;
  12  2   2   1;
  1   1   1   0]

my output1:

   1.0e+02 *

   1.7700 + 0.0000i  -1.0500 + 0.1400i   1.3700 + 0.0000i  -1.0500 - 0.1400i
  -0.1000 - 1.4700i  -0.0200 + 1.1100i  -0.0800 - 1.2100i  -0.2400 + 1.1300i
  -1.2900 + 0.0000i   1.1900 - 0.1200i  -1.0900 + 0.0000i   1.1900 + 0.1200i
  -0.1000 + 1.4700i  -0.2400 - 1.1300i  -0.0800 + 1.2100i  -0.0200 - 1.1100i

and my output2-

   1.0e+02 *

   1.7700 + 0.0000i  -1.0500 - 0.1400i   1.3700 + 0.0000i  -1.0500 + 0.1400i
  -0.1000 - 1.4700i  -0.2400 + 1.1300i  -0.0800 - 1.2100i  -0.0200 + 1.1100i
  -1.2900 + 0.0000i   1.1900 + 0.1200i  -1.0900 + 0.0000i   1.1900 - 0.1200i
  -0.1000 + 1.4700i  -0.0200 - 1.1100i  -0.0800 + 1.2100i  -0.2400 - 1.1300i

They have the same meanings, but change places in different positions! This made me go crazy for a long time because from what I read online, 2D FFT can be done by applying 1D FFT row by row and then column by column. Any help or suggestion would be great!

Answer 1

output1 = output1.' output1 = output1', .

function [output1, output2] = fft2D(input)
   output1 = input.';
   output1 = fft(output1);
   output1 = output1.';
   output1 = fft(output1);

   output2 = fft2(input);
end

, .

function [output1, output2] = fft2D(input)
   output1 = fft(input,[],1);
   output1 = fft(output1,[],2);

   output2 = fft2(input);
end